[E0515] I don't really understand lifetimes

Python programmer here. The way I understand lifetimes is that they're very similar to scope, if not the same.

I'm tryna make a function to extract a SSID profile's password, when I was greeted with E0515.

    fn get_password(profile: &String) -> Result<Match, String> {
        let output = Command::new("netsh")
            .args(["wlan", "show", "profile", profile, "key=clear"])
            .output();
    
        if output.is_err() {
            Err(output.unwrap_err().to_string())
        } else {
            let res = String::from_utf8(output.unwrap().stdout).unwrap();
            let parser = Regex::new(&SSID_KEY_REGEX).unwrap();
    
            Ok(parser.find(&res).unwrap())
        }
    }

I think it says that res's lifetime is too short, but I don't know how to "lengthen" that lifetime, to put it in words.

error[E0515]: cannot return value referencing local variable `res`
  --> src/main.rs:70:9
   |
70 |         Ok(parser.find(&res).unwrap())
   |         ^^^^^^^^^^^^^^^----^^^^^^^^^^^
   |         |              |
   |         |              `res` is borrowed here
   |         returns a value referencing data owned by the current function

How do I make it so that res doesn't get dropped by the end of get_password?

I have tried the following, to no avail:

• res.clone().as_str()
• res.to_owned().as_str()