Vec<T> to Vec<U> conversion
Why isn't From<Vec<T>> a default implementation for Vec<U> when From<T> is implemented for some U?
I thought I could just do let vec_u = vec_t.into() if I implement From<T> for U
Why isn't From<Vec<T>> a default implementation for Vec<U> when From<T> is implemented for some U?
I thought I could just do let vec_u = vec_t.into() if I implement From<T> for U